Specify # of bars in a row that have close higher than open

[yeahdudeman]

I know how to do this by doing the following:

if ((Close[0] > Open[0])
&& (Close[1] > Open[1])
&& (Close[2] > Open[2])
&& (Close[3] > Open[3])
&& (Close[4] > Open[4])

But what if I want to specify a custom amount of bars using a variable? For instance if I want to enter only when there are 100 bars in a row that have the close above the open. I know I could just keep doing what I did above up to 100 but is there a way to specify "enter when x # of bars in a row have a close higher than open" with a simple line of code?

Thanks!

[NinjaTrader_Emily]

Hello yeahdudeman,

Thank you for your post.

What you are looking for could be achieved with a for loop that loops through the Close > Open condition for the last 100 bars and keeps a tally of how many of the bars have the close above the open in an int variable. Here is an example loop:

greenBars = 0;
for (int i = 0; i <= 100; i++)
{
if (Close[i] > Open[i])
greenBars = greenBars + 1;
}

if (greenBars = 100)
EnterLong();

Please let me know if I may be of further assistance.