Math issue dividing an integer

[ATMtrader0001]

OK, here's my issue. I have an integer value that I want to divide by 100 and assign the results to a double. e.g. below:
int iIntValue;
double dOrderPrice;
double dResult;

iIntValue = 20;
dOrderPrice = Position.AveragePrice;
dResult = dOrderPrice - (iIntValue / 100);

When I do a Print(dOrderPrice + " : " +dResult + " : " +iIntValue);
I get:
87.69 : 0 : 20
when I expect to get:
87.69 : 0.2 : 20

I should be able to divide an integer and get a double. Is there a reason that this math would not work?

[NinjaTrader_ChrisL]

Hi, thanks for posting. You should cast the 100 to a double ((double)100) or add a .0 to the end of the value to make it a double and iIntValue should also be a double. It will truncate the fractional value if you use an integer.

Kind regards,
-ChrisL

[ATMtrader0001]

I did a work around by assigning the int value to a local double variable and then dividing by 100.
I have not seen this behavior before.

[ATMtrader0001]

Thank you for the feedback. I verified it does the same in Visual Studio for C#. Apparently I don't code enough C# to notice.

Closed.