Calculating if Close[0] is a round number

[nikolaalx]

Hi,
I am trying to calculate the current price in order to see if it is a round number....but can't seem to figure out a way to do it.

I am thinking of dividing Close[0] by a variable and then verifying if it is an integer.


{Close[0] / 50 = var1;}

And then to check if Var1 == whole number


Any input would be greatly appreciated.

Thanks.

[NinjaTrader_AlexG]

Hello,
Thanks for posting today.

Can you give a little clarification of what you mean by a round number? Are you asking if the number was previously rounded? Do you mean a whole number? Even?

I look forward to your reply.

[koganam]

Hi,
I am trying to calculate the current price in order to see if it is a round number....but can't seem to figure out a way to do it.

I am thinking of dividing Close[0] by a variable and then verifying if it is an integer.


{Close[0] / 50 = var1;}

And then to check if Var1 == whole number


Any input would be greatly appreciated.

Thanks.

if ((Close[0] - (int)Close[0]) == 0) {//Close[0] is a whole number, with no fractional part that is not also zero.}

[nikolaalx]

I apologize if it was a bit unclear, but my mother tongue is not English.

It would be easier to give an example.

I want to be able to tell if the price is a multiple of a given number. My goal is to be able to identify key price action levels.

E.g. if I set my multiple to be 50, then if Close[0] is 2000, 2050, 2100, 2150 to have my signal.

Original Idea was to divide the closing price by the multiple, and then to see if the output is an integer.

E.g. if Close[0] is 2000, then to divide it by 50 and the result would be 40.

If the Close[0] is 2001, dividing it by 50 would not result in an integer but rather a double digit.

Hello,
Thanks for posting today.

Can you give a little clarification of what you mean by a round number? Are you asking if the number was previously rounded? Do you mean a whole number? Even?

I look forward to your reply.

[NinjaTrader_AlexG]

Hello nikolaalx,
Thanks for the reply.

You can use the modulus operator (%) to determine if a number is divisible by the divisor.

If for example you did
Print(5000 % 50); //output would be 0 since 50 goes into 5000 evenly without a remainder.

So if you did
if (Close[0]% 50 !=0 )

then the number has a remainder.

Please let us know if we may be of further assistance for anything NinjaTrader.