Problems with the detection ChartTrader

[vladko]

System.Windows.Controls.Grid chartGrid2 = (Window.GetWindow(ChartControl.Parent).FindFirst("ChartWindowChartTraderControl") as ChartTrader).Parent as System.Windows.Controls.Grid;

This code works fine when you first start.

Then if you remove ChartTrader from the chart, this code still shows the presence of ChartTrader on the chart

[NinjaTrader_Jesse]

Hello,

Thank you for the question.

I wanted to check, are you trying to determine when the chart trader is open and enabled vs closed and enabled vs closed and disabled?

The visibility of the control is being toggled rather than the control being actually removed so there should still be an instance on the actual parent control.

If you can tell me what the end result you are expecting is, I could see if there is a better way to accomplish that.

I look forward to being of further assistance.

[vladko]

open and enabled vs closed and disabled

chartGrid2 should be null if ChartTrader is disabled

I want to know is whether cartrader now on the chart

Ideally, of course know all 3 states: off, on, hidden

[NinjaTrader_Jesse]

Hello,

To know if the ChartTrader is Enabled vs Hidden vs Disabled you could check the ChartTraderVisibility of the ChartTrader object rather than checking for null.

Here is a sample with the output:

ChartControl.Dispatcher.InvokeAsync((Action)(() => {  
		ChartTrader trader = Window.GetWindow(ChartControl.Parent).FindFirst("ChartWindowChartTraderControl") as ChartTrader;
		if(trader!= null)
		{
			Print(trader.ChartTraderVisibility.ToString());	
			//Open    = Visible
			//Hidden  = VisibleCollapsed
			//Closed  = Collapsed
		}
	}));

I look forward to being of further assistance.

[vladko]

OK, Thank You