BUG: built-in Slope() method incorrect

[eDanny]

I'm trying to figure out what ticks has to do with slope besides using ticks to calculate slope. Please clarify the clarification!

[mgbloomfield]

Think of ticks (price) as the y-axis and period (time) as the x-axis.

[eDanny]

Think of ticks (price) as the y-axis and period (time) as the x-axis.

I know that, and ticks would be used to figure slope on price but I dont understand the request to get the slope in ticks since slope is angle.

[mgbloomfield]

I know that, and ticks would be used to figure slope on price but I dont understand the request to get the slope in ticks since slope is angle.

Agreed. I don't want the slope in ticks. Slope is an angle.

[eDanny]

Here is what I use for an indicator slope:

MyAngle.Set(Math.Atan(Slope(MACD(12,26,9).Avg, 1,0)) * 180/Math.PI);

which checks angle between current and 1 bar back I haven't tried to apply directly to price.

Would this work?

MyAngle.Set(Math.Atan(Slope(Close), 1,0)) * 180/Math.PI);

Not what I expected.

This:

Print("angle " + (Math.Atan(Slope(Close, 3,0) * 180/Math.PI)));

outputs this:

angle -1.36434100921404
angle -1.46645686609606
angle 0
angle 1.36434100921404
angle 1.36434100921404
angle 1.46645686609606
angle 1.54752946948938
angle 1.55175867160589
angle 1.55334480614343
angle 1.52893289777454

[NinjaTrader_JoshP]

You would need to close the arctangent before multiplying 180/Math.PI. You may want to look around in google to see if this is the proper procedure to convert radians to degrees.

[eDanny]

My bad when changing to the Print statement. This is better:
angle -4.76364169072618
angle -9.46232220802562
angle 0
angle 4.76364169072618
angle 4.76364169072618
angle 9.46232220802562
angle 36.869897645844
angle 42.5104470780008
angle 45
angle 22.6198649480404