Min number in list > SomeNumber

[nelslynn]

I'm struggling to find the smallest number from a list of Double numbers that is greater than another number.

EXAMPLE:
List (30, 38, 40, 50, 56)
SomeNumber = 35
Want to return 38

I know there is something like this:
var list = new[] {30 ,38, 40, 50, 56};
MinNumber = list.Min();

but how do I fit the condition of greater than SomeNumber in there?

Thanks!

[NinjaTrader_ChelseaB]

Hello nelslynn,

Make a new list of numbers that meet the criteria then use the <Enumerable>.Min().

https://learn.microsoft.com/en-us/dotnet/api/system.linq.enumerable.where?view=netframework-4.8.1

https://learn.microsoft.com/en-us/dotnet/api/system.linq.enumerable.min?view=netframework-4.8.1

list.Where( num => num > SomeNumber ).Min()

[nelslynn]

Here's what I came up with based on the references you gave. Can I not use this with double numbers?

List<double> MyList= new List<double> {30, 38.223, 40, 50, 56.23};

IEnumerable<double> query = MyList.Where(MyList < SomeNumber);
MyValue = query.Min();

I get this error:
Operator '<' cannot be applied to operands of type 'List<double> and 'double'

[NinjaTrader_ChelseaB]

Hello nelslynn,

It looks like you have changed the name of the 'list' variable to 'MyList'. The updated code would appear:

MyList.Where( num => num > SomeNumber ).Min()

See post # 2 where I have made this suggestion.


"Can I not use this with double numbers?"

A List<double> is a collection of multiple values.

A double is one value.

You cannot compare an entire collection of values to one value.

Instead use the code I have suggested, which is comparing each value in the collection, one at a time, held by the 'num' variable, to the 'SomeNumber' double variable.