ProfitTarget as difference between entry price and indicator value

[Deep_ITM_Puts]

Hi,

I'm working on coding a strategy and having trouble with the profit target. Also couldn't find any similar threads.

I'll use a made up up scenario for the sake of explaining. Let's say we enter a short trade when NQ is at 13,500.00 and the EMA is currently at 13,400.00. That would be a 400 tick difference.

How would I code such a scenario where I want to use that amount as the profit target or set the profit target as entry price minus indicator value like the example above? Or even a multiple like....1.5 times the difference between entry price and current EMA value like Entry(13,500) - EMA (13,400) = 400 ticks*1.5= 600tick profit target.

Thanks for any guidance. I've been trying to code this the following way to no avail....

SetProfitTarget(CalculationMode.Ticks, (Position.AveragePrice-EMA[0]*1.5);

[NinjaTrader_ChelseaB]

Hello Deep_ITM_Puts,

With Set methods, use CalculationMode.Price to set the order to a specific price and not to a distance in ticks.
https://ninjatrader.com/support/help...ofittarget.htm

Use a different variable name than EMA as this is already used for the EMA indicator and causes ambiguity.

private EMA myEMA;

myEMA = EMA(13);

Print out 'Position.AveragePrice - myEMA[0] * 1.5' to see if this is the value you are looking for.

if (Position.MarketPosition != MarketPosition.Flat)
{
Print(string.Format("{0} | Position.AveragePrice: {1} - myEMA[0]: {2} * 1.5 = {3}", Time[0], Position.AveragePrice, myEMA[0], (Position.AveragePrice - myEMA[0] * 1.5)));
}

https://ninjatrader.com/support/foru...121#post791121

Reset set methods before placing a new entry by calling the set method with a number of ticks, as these cannot be unset.

Below is a link to an example ProfitChaseStopTrailSetMethodsExample_NT8 which demonstrates.
https://ninjatrader.com/support/foru...269#post802269

I am also including a link to a forum post with helpful resources on getting started with C# and NinjaScript.
https://ninjatrader.com/support/foru...040#post786040