Triangles and angles

[fishbed]

Hi

Is there any way when creating a triangle from 3 points, overlayed on a chart, that I would be able to calculate the internal angles?

I can initially think to use the number of bars (x axis) and price (y axis) but obviously these values are not related in any way to each other and therefore any angle produced would not necessarily be accurate.

Would I be able to get at he length of the lines in pixels or any form of measurement scale?

Any thoughts appreciated.
Thanks

[NinjaTrader_Jim]

Hello fishbed,

Thanks for opening the thread.

You could use some trigonometry to calculate the angle based off of the slope of each line. You could calculate the slope using the drawing objects anchors. I can think of a couple implications while considering this.

Using Price levels and bar indexes would keep the slope consistent in a price vs bar index perspective, but would not reveal a true angle in the charts scale.

Using the pixel coordinates from the anchors to calculate slope will give you a truer angle in relativity to the chart, but the chart's auto scale setting should be noticed when calculating the slope from these anchors. If the charts scale changes, so will the angles. I would advise to override OnCalculateMinMax() and recalculate your slopes there to maintain accurate angles.

ChartAnchor.GetPoint() - https://ninjatrader.com/support/help...s/getpoint.htm

DrawObjects (to be referenced for looping through DrawObjects) - https://ninjatrader.com/support/help...rawobjects.htm

OnCalculateMinMax() - https://ninjatrader.com/support/help...lateminmax.htm

You can use an inverse tangent to calculate the angle from slope.

https://www.archtoolbox.com/measurements/geometry/slope.html

https://msdn.microsoft.com/en-us/library/system.math.atan(v=vs.110).aspx

Please let me know if I may be of further assistance.

[fishbed]

triangle angles

HI Jim

Thanks for this, it is given me a lot to ponder and look through.

Regards

[JerryWar]

Rather than Bars or Pixels why not use Price(y) and Time(x) given NT8 has
better time resolution than NT7.