Count sessions and return if more then 3 from current

[memonolog]

Count sessions and return if more then 3 from current

Hello everyone, I am using the code with the condition on which the ray is drawn. the task is to set the ray rendering (condition true) if the ray was drawn more than 3 sessions ago. how you can count sessions and return if the condition is met in a session that was greater than the current one by more than 3. thank you very much in advance.

ps / in my code I use SessionIterator

[NinjaTrader_ChelseaB]

Hello memonolog,

The easiest way would be to have an int counter set to 0 when the object is drawn, that is incremented when Bars.IsFirstBarOfSession is true. This would count number of sessions since the object was drawn.

https://ninjatrader.com/support/helpGuides/nt8/isfirstbarofsession.htm

With a sessionIterator, you could use .AddDays() to a datetime and check each day to see if the next session start matches the current session start.

https://ninjatrader.com/support/helpGuides/nt8/getnextsession.htm

I think it would likely be less difficult but still advanced to directly loop through the TradingHours.Sessions collection.

https://ninjatrader.com/support/helpGuides/nt8/tradinghours_sessions.htm

[memonolog]

Hello memonolog,

The easiest way would be to have an int counter set to 0 when the object is drawn, that is incremented when Bars.IsFirstBarOfSession is true. This would count number of sessions since the object was drawn.
https://ninjatrader.com/support/help...rofsession.htm

With a sessionIterator, you could use .AddDays() to a datetime and check each day to see if the next session start matches the current session start.
https://ninjatrader.com/support/help...extsession.htm

I think it would likely be less difficult but still advanced to directly loop through the TradingHours.Sessions collection.
https://ninjatrader.com/support/help...s_sessions.htm

at least one live code example is implemented somewhere in indicators? like the last one?

for now i found such a solution, but this is not really what I need, I just need to limit the work if 3 sessions are more than the current one

if (Time[0] < DateTime.Now.AddDays(-MaxDaysToLoad)) // if current bar being processed is older than 3 days ago return
return;

[memonolog]

Hello memonolog,

The easiest way would be to have an int counter set to 0 when the object is drawn, that is incremented when Bars.IsFirstBarOfSession is true. This would count number of sessions since the object was drawn.
https://ninjatrader.com/support/help...rofsession.htm

With a sessionIterator, you could use .AddDays() to a datetime and check each day to see if the next session start matches the current session start.
https://ninjatrader.com/support/help...extsession.htm

I think it would likely be less difficult but still advanced to directly loop through the TradingHours.Sessions collection.
https://ninjatrader.com/support/help...s_sessions.htm

what will be the correct syntax for the analogue of this code

if (Time[0] < DateTime.Now.AddDays(-MaxDaysToLoad)) // if current bar being processed is older than 3 days ago return
return;

But using With a sessionIterator??

sessionIterator.GetNextSession(Times[1][1], true);

// store the desired session information
DateTime tradingDay = sessionIterator.ActualTradingDayExchange;
DateTime beginTime = sessionIterator.ActualSessionBegin;
DateTime endTime = sessionIterator.ActualSessionEnd;

if (Time[0] > endTime.AddDays(-1))

is that right?

[NinjaTrader_PaulH]

Hello memonolog,

Thanks for your reply.

Perhaps a simpler approach, as Chelsea suggested, may help here.

Create an integer variable to count the sessions.

On the first bar of the session, increment the counter.

For example: private int sessionCounter = 0;

if (Bars.IsFirstBarOfSession)
{
sessionCounter +=; // incremnt counter
}

if (sessionCounter == 3)
{
// do something
}

[memonolog]

Hello memonolog,

Thanks for your reply.

Perhaps a simpler approach, as Chelsea suggested, may help here.

Create an integer variable to count the sessions.

On the first bar of the session, increment the counter.

For example: private int sessionCounter = 0;

if (Bars.IsFirstBarOfSession)
{
sessionCounter +=; // incremnt counter
}

if (sessionCounter == 3)
{
// do something
}

if (Bars.IsFirstBarOfSession)
{
sessionCounter +=; // incremnt counter
}

I get error here

[NinjaTrader_PaulH]

Hello memonolog,

Thanks for your reply.

Sorry for my typing error, please try:

if (Bars.IsFirstBarOfSession)
{
sessionCounter += 1; // increment counter
}

[memonolog]

Hello memonolog,

Thanks for your reply.

Sorry for my typing error, please try:

if (Bars.IsFirstBarOfSession)
{
sessionCounter += 1; // increment counter
}

I tried it, it doesn't work, the code is executed from all sessions loaded on the chart,

but I need to have a return (the code did not work from previous sessions if these sessions are older than the current one by more than 3)

I have code

 if (Time[0] < DateTime.Now.AddDays(-2)) // if current bar being processed is older than 3 days ago return
return;

this code works, but it has a problem with weekends, since it counts days and not sessions
are there other solutions to solve the problem?

[NinjaTrader_PaulH]

Hello memonolog,

Thanks for your reply.

If your code works but not on weekends then a simple solution is to check to see if the day is Monday and if to then subtract additional days.

if (Time[0].DayOfWeek == DayOfWeek.Monday)

[joselube001]

Thank you memonolog for this code:

if (Time[0] < DateTime.Now.AddDays(-MaxDaysToLoad)) // if current bar being processed is older than 3 days ago return
return;

This make great improvements to load the indicator in data series with a large numbers of days, loading only last 7 days of the indicator needed to make analysis and give context!
I will not need to use 2 data series to improve the loading of the indicators anymore!
THANK YOU!!!