Get x,y position of current window

[iq200]

Hi,
Is there a way to get the x, y (in windows terms, the top, left) position of the chart window in which I have added an indicator, within the indicator code?
Thank-you,
iq

[NinjaTrader_Jesse]

Hello iq200,

Are you referring to the actual window position or are you referring to the X/Y inside of the chart panel that your indicator can render to?

You can get either however those are different concepts.

The ChartPanel object exposes the charts sizes: https://ninjatrader.com/support/help...chartpanel.htm
You can see the SampleCustomRender indicator for examples of rendering to the corners of the chart.

If you otherwise meant the window you can access its WPF window properties like the following:

ChartControl.Dispatcher.InvokeAsync((Action)(() =>
{

                //Obtain the Chart on which the indicator is configured
                chartWindow = Window.GetWindow(this.ChartControl.Parent) as Chart;
                chartWindow.Top
                chartWindow.Left
});

I look forward to being of further assistance.

[iq200]

HI Jesse,
I was referring to the actual window (which contains the chart) position on the screen.
The reason I'm asking is that I'm creating an external window and I need to arrange this window alongside the chart window.
Right now, the external window gets created based on a location determined by Windows.
It looks like the snippet you posted should do the job.
Thank-you for your help.
Regards,
iq