Rounded numbers from print statement

[Diepy]

Hi Folks,

Newbee question: I want to express one value in relation to another as a percentage. When testing this in the output window I get rounded numbers only, either 1 or 0.

The variable I tried is both double and float but output stays the same, the statement is below:

_50PercDelta = (barsType.Volumes[CurrentBar].TotalVolume + barsType.Volumes[CurrentBar].MinSeenDelta) / barsType.Volumes[CurrentBar].TotalVolume;

What am I missing here?

[NinjaTrader_Jim]

Hello Diepy,

Thanks for your post.

We are seeing the result of integer math being assigned to a double because you are performing mathematical operations on integers and assigning the result to a double.

You could consider casting (publicly available resource) the integers to type double, and we will then see a result from floating point arithmetic.

We look forward to assisting.

[Diepy]

Thanks Jim, that makes sense.

So double would be fine for my purposes and I figured I would alter the statement like below.

_50PercDelta = Convert.ToDouble((barsType.Volumes[CurrentBar].TotalVolume + barsType.Volumes[CurrentBar].MinSeenDelta)/ barsType.Volumes[CurrentBar].TotalVolume)

The output window still shows rounded numbers though, anything I am missing still?

Thanks

[NinjaTrader_Jim]

Hello Diepy,

You are still performing math on integers, getting a result from integer math, AND THEN you are converting to a double, and assigning to the double variable.

Try casting the integers before performing the math. I.E.

((double)(barsType.Volumes[CurrentBar].TotalVolume) + (double)(barsType.Volumes[CurrentBar].MinSeenDelta) / (double)(barsType.Volumes[CurrentBar].TotalVolume;

OR

(Convert.ToDouble(barsType.Volumes[CurrentBar].TotalVolume) + Convert.ToDouble(barsType.Volumes[CurrentBar].MinSeenDelta) / Convert.ToDouble(barsType.Volumes[CurrentBar].TotalVolume;

[Diepy]

Thanks Jim, I see I was a too lazy programmer :-) Your suggestion did the trick, thanks for the help!