Doji for a strategy question

[outsource]

Hello outsource,

In your modified logic, your script is first going to check if High[0] > High[1] AND if Low[0] < Low[1]. If both of these conditions are true, thickMet is set to true.

Now if both of these conditions are NOT true, or if just one is NOT true, your script is going to evaluate your else if statement. If High[0] equals High[1], then thickMet is set to true.

Please note that in a conditional statement, you need to check for equality with two equal signs (==).

else if (High[0] == High[1])

Hi Zachary,

thanks for your reply.

what i need is that both conditions to be true,and on the third(if true) i want to enter.I need them to appear consequently.So,whould this one give me what i need?

if(! thickMet)
    {         if ( (High[0] > High[1]) && (Low[0] < Low[1]) )
         {
            [B]thickMet = true;[/B]
        }

         else    if ( High[0] == High[1] )
         {
            [B]thickMet = true;[/B]
         }
    }
    else
    { if ( (High[0] < High[1]) && (Low[0] > Low[1]) )
         {
            // [B]do stuff[/B]
        }
    }

[lmatiukas]

hey there,

still not as familiar with C# as I have to be, but from phyton and Java days, I have to assume you should use a while{} operator. Put the two conditions 1 && 2 you want, and then draw IF (third condition == true) { execute}

Sorry I'm not providing exact code needed with syntax, but it's super late, and I would have to compile it myself to test for potential errors

[NinjaTrader_ZacharyG]

Hello outsource,

Can you please clarify if this is what you are looking for?

// checks if both condition1 and condition2 are true
// if both conditions are true, check if condition3 is true
if (condition1 && condition2)
{
     // if condition3 is true, enter
     if (condition3)
          // enter
}

[outsource]

Hello outsource,

Can you please clarify if this is what you are looking for?

// checks if both condition1 and condition2 are true
// if both conditions are true, check if condition3 is true
if (condition1 && condition2)
{
     // if condition3 is true, enter
     if (condition3)
          // enter
}

Hi Zachary,

Yes,if condition1 true and condition2 true(consequently),then if condition3 true - enter.

[NinjaTrader_ZacharyG]

Hello outsource,

I have provided sample syntax on how to accomplish this in my previous post.

You will just need to replace condition1, condition2, and condition3 with your conditions.

Hello outsource,

Can you please clarify if this is what you are looking for?

// checks if both condition1 and condition2 are true
// if both conditions are true, check if condition3 is true
if (condition1 && condition2)
{
     // if condition3 is true, enter
     if (condition3)
          // enter
}

[outsource]

Hello outsource,

I have provided sample syntax on how to accomplish this in my previous post.

You will just need to replace condition1, condition2, and condition3 with your conditions.

So i don`t need to compare and don`t need to use thickMet function?

[NinjaTrader_ZacharyG]

Hello outsource,

I am not clear of what you are requesting.

Hi Zachary,

Yes,if condition1 true and condition2 true(consequently),then if condition3 true - enter.

// if condition1 AND condition2 are true, check if condition3 is true
if (condition1 && condition2)
{
     // if condition3 is true, call entry logic
     if (condition3)
          // enter
}

I do not know what your thickMet boolean is used for and I am not quite clear by what you mean by "so I don't need to compare."

Please clarify what you are asking for.

[outsource]

Hello outsource,

I am not clear of what you are requesting.

// if condition1 AND condition2 are true, check if condition3 is true
if (condition1 && condition2)
{
     // if condition3 is true, call entry logic
     if (condition3)
          // enter
}

I do not know what your thickMet boolean is used for and I am not quite clear by what you mean by "so I don't need to compare."

Please clarify what you are asking for.

It`s explained here:

http://ninjatrader.com/support/forum/showpost.php?p=461827&postcount=22

All i want now is to add some extra second condition.Originaly it was two conditions:

if first true,and then the second true - enter.

Now it`s:

if first true and the second true(all intrabar) and next, on third enter,if true.That`s it.

[outsource]

Jessica provided the example:

private bool thickMet = false;
protected override void OnBarUpdate()
{

    // ...

    if(FirstTickOfBar)
    {
        thickMet = false;
    }

    if(! thickMet)
    {         if ( (High[0] > High[1]) && (Low[0] < Low[1]) )
         {
            thickMet = true;
        }
    }
    else
    { if ( (High[0] < High[1]) && (Low[0] > Low[1]) )
         {
            // do stuff
        }
    }
}

Which works as expected.But now i wonder if i can add the second condition before the execution.For example:

private bool thickMet = false;
protected override void OnBarUpdate()
{

    // ...

    if(FirstTickOfBar)
    {
        thickMet = false;
    }

    if(! thickMet)
    {         if ( (High[0] > High[1]) && (Low[0] < Low[1]) )
         {
            thickMet = true;
        }
    }
[B] if(! thickMet)
    {         if (second condition)
         {
            thickMet = true;
        }
    }[/B]
    else
    { if ( (High[0] < High[1]) && (Low[0] > Low[1]) )
         {
            // do stuff
        }
    }
}

Would this one work properly???

[NinjaTrader_ZacharyG]

Hello outsource,

On each call of OnBarUpdate(), your edited code is going to:

1. Check if OnBarUpdate() was called on the first tick of a bar. If true, change thickMet to false
2. Check if thickMet is false. If it's false, check if the current high is more than the previous high AND if the current low is less than the previous low. If this condition is true, set the thickMet to true
3. Check again if thickMet is false. If it's false, check if the second condition is true. If the second condition is true, change thickMet to true.
4. If thickMet is TRUE when evaluating the second if (!thickMet) condition in bold (which is checking to see if thickMet is FALSE), the second condition will not be evaluated. The else code block will run instead and check if the current high is less than the previous high AND if the current low is more than the previous low. If this is true, run the // do stuff logic.

The else block of your code will not evaluate if the second if (!thickMet) condition in bold is true.

If this is not what you are wanting in your code, please provide a psuedocode sample of the behavior you are wishing to see.

I would highly suggest taking a look at this publicly available link for further information about if, else, and else if statements: http://www.techotopia.com/index.php/...th_if_and_else

[outsource]

Hi Zachary,

would that be more correct?

private bool thickMet = false;
protected override void OnBarUpdate()
{

    // ...

    if(FirstTickOfBar)
    {
        thickMet = false;
    }

    if(! thickMet)
    {         if ( (High[0] > High[1]) && (Low[0] < Low[1]) )
         {
            thickMet = true;
        }
    }
    [B]else[/B]
    {         if (second condition)
         {
            thickMet = true;
        }
    }
    else
    { if ( (High[0] < High[1]) && (Low[0] > Low[1]) )
         {
            // do stuff
        }
    }
}

[NinjaTrader_ZacharyG]

Hello outsource,

Have you attempted to compile the syntax you have written?

If-else-else is not proper syntax.

You will need to do if-ELSE IF-else

As an example:

if (condition1)
{
     // do something
}
else if (condition2)
{
     // do something
}
else
{
     // do something
}

if (!thickMet)
{
     if((High[0] > High[1]) && (Low[0] < Low[1]))
          thickMet = true;
}
else if (second condition)
     thickMet = true;
else
{
     if ((High[0] < High[1]) && (Low[0] > Low[1]))
          // do stuff
}

I would not be able to tell you if this would be "more correct" or not. You will need to see how this code will be logically evaluated and then determine if this is what you desire.

In summary, your logic does the following:

1. If being evaluated on the first tick of bar, set thickMet to false
2. Check if thickMet is false. If thickMet is false, check if High[0] > High[1] AND Low[0] < Low[1]. If this condition is true, change thickMet to true. The rest of the code (second condition and last condition) will not evaluate regardless of the result of the High[0] > High[1] AND Low[0] < Low[1] check.
3. If the condition, if (!thickMet), is false, evaluate the second condition. If the second condition is true, set thickMet to true. The rest of the code (the last condition) will not evaluate if second condition is true.
4. If second condition AND if (!thickMet) are both false, the last condition will evaluate. If this is true, run the // do stuff code

If this is not what you are wanting in your code, please provide a psuedocode sample of the behavior you are wishing to see.

I would highly suggest reading this article from DotNetPerls for further information about if, else if, and else: http://www.dotnetperls.com/if

[outsource]

Hello outsource,

Have you attempted to compile the syntax you have written?

If-else-else is not proper syntax.

You will need to do if-ELSE IF-else

As an example:

if (condition1)
{
     // do something
}
else if (condition2)
{
     // do something
}
else
{
     // do something
}

if (!thickMet)
{
     if((High[0] > High[1]) && (Low[0] < Low[1]))
          thickMet = true;
}
else if (second condition)
     thickMet = true;
else
{
     if ((High[0] < High[1]) && (Low[0] > Low[1]))
          // do stuff
}

I would not be able to tell you if this would be "more correct" or not. You will need to see how this code will be logically evaluated and then determine if this is what you desire.

In summary, your logic does the following:

1. If being evaluated on the first tick of bar, set thickMet to false
2. Check if thickMet is false. If thickMet is false, check if High[0] > High[1] AND Low[0] < Low[1]. If this condition is true, change thickMet to true. The rest of the code (second condition and last condition) will not evaluate regardless of the result of the High[0] > High[1] AND Low[0] < Low[1] check.
3. If the condition, if (!thickMet), is false, evaluate the second condition. If the second condition is true, set thickMet to true. The rest of the code (the last condition) will not evaluate if second condition is true.
4. If second condition AND if (!thickMet) are both false, the last condition will evaluate. If this is true, run the // do stuff code

If this is not what you are wanting in your code, please provide a psuedocode sample of the behavior you are wishing to see.

I would highly suggest reading this article from DotNetPerls for further information about if, else if, and else: http://www.dotnetperls.com/if

Yes,it compiles,but it`s hard to tell visually if it`s working..

[outsource]

In summary, your logic does the following:

1. If being evaluated on the first tick of bar, set thickMet to false
2. Check if thickMet is false. If thickMet is false, check if High[0] > High[1] AND Low[0] < Low[1]. If this condition is true, change thickMet to true. The rest of the code (second condition and last condition) will not evaluate regardless of the result of the High[0] > High[1] AND Low[0] < Low[1] check.
3. If the condition, if (!thickMet), is false, evaluate the second condition. If the second condition is true, set thickMet to true. The rest of the code (the last condition) will not evaluate if second condition is true.
4. If second condition AND if (!thickMet) are both false, the last condition will evaluate. If this is true, run the // do stuff code

Zachary,all in all,

I wan`t the code to evaluate all three conditions to be true.So,if the first condition is true,then evaluate the second one,if the second one is true,evaluate the third one,if the third one is also true - do stuff.

[NinjaTrader_ZacharyG]

Hello outsource,

Thank you for the clarification.

You'll want to look into making a nested if statement.

Here is an example:

if (condition1)
{
     if (condition2)
     {
          if (condition3)
          {
               // do something
          }
    }
}

In the example above, if condition1 is true, evaluate condition2. If condition2 is true, evaluate condition3. If condition3 is true, do something.