Volume()

[Imran]

Hi Guys,

Is this the correct syntax for the Checking that the average size of the most recent 8th volume bar is greater than 30% in size than the preceding volume bars.

VOL()[0] > (VOL()[8]) * (1 + 0.3)

How it will check the all previous 8 bars or the only previous single 8th bar.


Thanks
Imran.

[NinjaTrader_ChelseaB]

Hello Imran,

Thank you for your note.

Your syntax is correct however your logic is not.

Your current code checks to see if the Vol current bar is 30% greater than the Vol of 8 bars ago.

To check that the individual Vol bar 8 bars ago is 30% greater than the series preceding it you would to check that Vol bar 8 bars ago * 1.3 is greater than the Max of vol using 8 bars ago.
For example:
(Vol()[8] * 1.3) > Max(Vol(), 20)[9]
Max(Input Series, period)[bars ago]

The period of 20 refers to the amount of bars the Max function will look over. This is to prevent it looking through all of the available historical bars which would be very resource intensive when a lot of historical data is available.

Below is a link to the help guide on using the Max function
http://www.ninjatrader.com/support/h...aximum_max.htm

Please let me know if I can be of further assistance.

[Imran]

Hi ChelseaB
Thanks for the your valuable response. I want to check the current bar is greater than 30% of the preceding 8 volume bars. | | | | | | | |

Please verify the code.

(Vol()[0] * 1.3) > Max(Vol(), 8)

Thanks
Imran.

[NinjaTrader_ChelseaB]

Hello Imran,

Thank you for the reply.

The updated code you supplied checks that the last bar increased by 30% is greater than the last 8 bars of Vol().

This logic is correct, however, I would make one change. You check that the current bar is greater than the last 8 bars. This will never be true as the last bar is included in the last 8 bars. The last bar will never be greater than itself. To correct this add 1 to the bars ago of the Max() call. This would exclude the last bar from the Vol series.

For example:
(Vol()[0] * 1.3) > Max(Vol(), 8)[1]


Please let me know if I can still be of assistance.