Two hooks

[MartinBrr]

Hi,

I have problem with programing two hooks on CCI.
Condition for long signal: CCI made a hook and an another hook (in next 2-8bars) is higher then first

I want to change period of CCI and lenght two hooks.

Hooks means that // Condition set 1
if (CCI(CCI_short)[2] > CCI(CCI_short)[1]
&& CCI(CCI_short)[0] > CCI(CCI_short)[1]
&& CCI(CCI_long)[2] > CCI(CCI_long)[1]
&& CCI(CCI_long)[0] > CCI(CCI_long)[1])



Please please, help me.

[NinjaTrader_JoshP]

MartinBrr,

I am not quite following what exactly you are trying to do. If you want to trade only if your condition occurs twice you can do this by creating a counter.

if (condition)
{
     hookCount++;
}

if (hookCount == 2)
{
     EnterLong();
     hookCount = 0;
}

[MartinBrr]

Thank you for answer, but I want do program this:
For long signal: There are two hooks on CCI in a row (2-8 candel /changeable/) and condition for second hooks-must be higher then first. (On both CCI, with long and short period)

MartinBrr,

I am not quite following what exactly you are trying to do. If you want to trade only if your condition occurs twice you can do this by creating a counter.

if (condition)
{
     hookCount++;
}
 
if (hookCount == 2)
{
     EnterLong();
     hookCount = 0;
}

[NinjaTrader_Bertrand]

MartinBrr, you can use the snippet Josh has provided for this - for the 'hook' you could simply state the CCI had changed direction and then count the number of bars between your conditions. To check if the hook in the CCI occurs at a higher price you would then need to save the CCI values of both hooks to variables and compare.

[saroj]

Seems that you also have to save the bar index (which bar it is) of the trough of the first "hook" (CCI(CCI_short)[1]) and that of the second to know if the two hooks occurred within 8 bars. and reset these 'start' / 'finish' points to either null or, if it fits your pattern criteria, put the previous 'finish' bar into the 'start' bar index while you are waiting for the next hook. You might think through at what point the pattern is no longer valid and then reset both 'start' and 'finish' to null. You might also put a paramenter in for the separation of occurrances so that you can optimize for it... ditto on the value of the CCI of the 2nd trough... you might not want to go long if CCI is greater than 150 for instance.