How can I measure the slope of a line?

[ELDAVIDOLOCO]

Hello, how can I measure the slope of a line, in Ninja Trader?


Thanks for the help.

[NinjaTrader_PatrickH]

Hello ELDAVIDOLOCO,

Thank you for your post.

Unfortunately, there is not a drawing tool to measure the slope. You can use Slope() in NinjaScript to measure the slope of a Plot/DataSeries: http://www.ninjatrader.com/support/h.../nt7/slope.htm

[arbuthnot]

Hello, how can I measure the slope of a line, in Ninja Trader?

Thanks for the help.

Even though, as Patrick says, there isn't a drawing tool to measure the slope, it can be calculated using some math that you may remember from school.

Let's say the start of the line is at Close[n] and the end at Close[0]. From geometry, we would say that X1 = n, Y1 = Close[n], X2 = 0 and Y2= Close[0].

The formula for the slope of such a a line is:

(X2 - X1)
-------------
(Y2 - Y1)

so in NinjaScript terms this comes out as:

double m = - n / (Close[0] - Close[n]);

(m being the conventional letter for 'slope'.)

Hope this helps.

[arbuthnot]

Looking at my last post, the formula can be simplified to avoid the 'stray' minus sign. It's easier to use:

double m = n / (Close[n] - Close[0]);

(the m is of course arbitary.)

[koganam]

Even though, as Patrick says, there isn't a drawing tool to measure the slope, it can be calculated using some math that you may remember from school.

Let's say the start of the line is at Close[n] and the end at Close[0]. From geometry, we would say that X1 = n, Y1 = Close[n], X2 = 0 and Y2= Close[0].

The formula for the slope of such a a line is:

(X2 - X1)
-------------
(Y2 - Y1)

so in NinjaScript terms this comes out as:

double m = - n / (Close[0] - Close[n]);

(m being the conventional letter for 'slope'.)

Hope this helps.

Not to quibble, but actually slope is rise/run. You have that the wrong way round.

[arbuthnot]

Thanks, Koganam!

You are right - I am wrong!

My math degree has been rescinded and I'm sliding down the slippery - er - slope?

At my third attempt, this is the equation:

double m = (Close[n] - Close[0]) / n;

I was in a bad mood today until I saw this: a wonderful example of my absent-mindedness!

It's important to quibble otherwise wrong information can be left in the Forum, which helps no one.

Much obliged to you for pointing this out.

Cheers!

Ed