Casting a Variable inside a loop... what is variable type next time loop runs

[Crassius]

Math in C# ties me in knots some times. I need someInt to be an int so its the correct type for use as an argument.

I need someDouble to be a double because someOtherDouble is a percentage ( like .025)

while (recordIn != null) 
    {
       someDouble = Math.Round(someDouble * someOtherDouble);
       someInt = (int) someDouble;
    }

I'm sure the above will work on the first run of this while loop.... but I don't know how long that cast of someDouble to a int lasts.

What type is someDouble on the SECOND run of he loop? Does the cast to int persist and it is now a int forever.... or does it revert back to its declared type as double... I declared it as private double in the variables section of a strategy....

Teaching myself as I go along so bear with me please

[Radical]

If everything is as you describe, I think it should remain as an int.

[Crassius]

What about promotion?

I just thought of something....

What about automatic promotion..... if the cast persists, on the second run of the loop, during the multiplication....

someDouble = Math.Round(someDouble * someOtherDouble);

won't someDouble get automatically promoted to a double again.... and will then be all set to get cast back to an int on the next line

someInt = (int) someDouble;

Then the loop will run again and it get promoted then cast again....

Can someone please confirm?

[Radical]

I'm not sure what you're asking, but with the line

someInt = (int)someDouble;

you are storing someDouble as an int in the variable 'someInt', you aren't modifying someDouble.

Edit: also, this post should answer your original question in this thread. Disregard my first post in this thread, I misread what you were asking.

[Crassius]

I'm not sure what you're asking, but with the line

someInt = (int)someDouble;

you are storing someDouble as an int in the variable 'someInt', you aren't modifying someDouble.

Ahh... yes that's the key to it... I needed to know if I was modifying someDouble into an int.... I was thinking maybe I was changing the type of someDouble from a double as declared to now be a int.

But I think I understand now... I am not changing someDouble's type... I am changing the value stored inside someDouble to an int and then storing it into someInt... leaving someDouble as type double.