Range Bars

["CJS"]

For some reason is not working fine.

It is just working the days in which the 4 Range chart has a 07 o'clock bar.

Is this the correct syntax?:
protected override void Initialize()
{

Add(PeriodType.Minute, 1);
}

protected override void OnBarUpdate()
{
if (BarsInProgress==1)
{
return;
}

if (ToTime(Times[1][0])==70000)
{
"Place Stop Orders..."

}

}

Thanks

[NinjaTrader_Bertrand]

CJS, to which series are you then submitting your orders? What is the TraceOrders output saying?

["CJS"]

I have a (4 Range) chart with the strategy. In the script I have added a 1 min series.

I use that 1 min series to get a reference value, which I store in a double variable. This value is the Open of the 7 o'clock bar.

if (ToTime(Times[1][0])==70000)
{
referenciaprecio = Opens[1][0];
}

I use this value (Open of the 7:00 bar) Ito build up the whole strategy everyday.

But, for some reason, in the 4 Range chart the strategy is working fine just those days with a 7:00 bar. If this bar do not exist, nothing happens that day.

Even though I have added the 1 min series, the problem could be that this 1 min series is almost everyday slower than the 4 Range. Generally, the 7 :00 1-min bar is within a 4 Range bar which took 3-4 minutes to form. Probably the problem is around this idea.

Nothing appers in the TraceOrders output those days.

[NinjaTrader_Bertrand]

CJS, please try something like this below from 24 / 7 ES chart for example, it should on the next range bar open after the 1 min hit the 7000 AM signal, Exit would be just on close then...just for demo purposes.

protected override void Initialize()
        {
            CalculateOnBarClose = true;
			Add(PeriodType.Minute, 1);
        }

        /// <summary>
        /// Called on each bar update event (incoming tick)
        /// </summary>
        protected override void OnBarUpdate()
        {
			if (BarsInProgress != 1)
				return;
			
			if (ToTime(Times[1][0]) == 070000 && Position.MarketPosition == MarketPosition.Flat)
				EnterLong(0, 1, "1Min wants to be long");
			
        }