assign Series<double> a double value in NT8

[stearno]

I am converting this indicator from NT7 to NT8. In NT7 I was using

Values[2].Set(double);

But now NT8 help said there is no more Set. But when I try to use the '=', it gives me an errror message that says "Cannot implicitly convert double to series<double>.

What should I use to yeild the same information in NT8 code?

Thanks

-Stearno

[Serialcoder]

Instead of Set(double) You will do this

Values[2][0] = double

I am converting this indicator from NT7 to NT8. In NT7 I was using

Values[2].Set(double);

But now NT8 help said there is no more Set. But when I try to use the '=', it gives me an errror message that says "Cannot implicitly convert double to series<double>.

What should I use to yeild the same information in NT8 code?

Thanks

-Stearno

[stearno]

Instead of Set(double) You will do this

Values[2][0] = double

Which number is the bars back in your example right here? The 2 or the 0?

[Serialcoder]

The 0. Set in NT7 automatically set position 0. To simplify if you only had 1 series in your indicator/strategy then it will be

Series<double> mySeries = new Series<double>(this);

//then this the NT8 implementation that would be similar to mySeries.Set(value)

mySeries[0] = value;

Which number is the bars back in your example right here? The 2 or the 0?

[koganam]

The 0. Set in NT7 automatically set position 0. To simplify if you only had 1 series in your indicator/strategy then it will be

Series<double> mySeries = new Series<double>(this);

//then this the NT8 implementation that would be similar to mySeries.Set(value)

mySeries[0] = value;

Succinctly, yes!

[stearno]

The 0. Set in NT7 automatically set position 0. To simplify if you only had 1 series in your indicator/strategy then it will be

Series<double> mySeries = new Series<double>(this);

//then this the NT8 implementation that would be similar to mySeries.Set(value)

mySeries[0] = value;

Thanks, that was helpful!