Rounding to the nearest integer...

[[email protected]]

Thank you Sledge and Koganam

I will make some adjustments and keep you posted. Thanks!!

[koganam]

does not work...................

#region Variables
private int period = 14;
private int trueRangeInt = 0;
private double trueRange = 0;
#endregion
.
.
.
.
.

if (CurrentBar == 0)
Value.Set(High[0] - Low[0]);
else
{
trueRange = High[0] - Low[0];
trueRange = Math.Max(Math.Abs(Low[0] - Close[1]), Math.Max(trueRange, Math.Abs(High[0] - Close[1])));
trueRange = trueRange / 0.03125;
trueRangeInt = (int) trueRange;
Value.Set(((Math.Min(CurrentBar + 1, Period) - 1 ) * Value[1] + (int) trueRange) / Math.Min(CurrentBar + 1, Period));
}
.
.
.
It displays x.xx not x

why???

thanks.

Value is always a double, so your expression will always be evaluated and displayed as a double.

[sledge]

What is Value[1]?

print that out. That looks like your weak link.

[[email protected]]

Can we idiots get a clear example? thanks.

does not work...................

#region Variables
private int period = 14;
private int trueRangeInt = 0;
private double trueRange = 0;
#endregion
.
.
.
.
.

if (CurrentBar == 0)
Value.Set(High[0] - Low[0]);
else
{
trueRange = High[0] - Low[0];
trueRange = Math.Max(Math.Abs(Low[0] - Close[1]), Math.Max(trueRange, Math.Abs(High[0] - Close[1])));
trueRange = trueRange / 0.03125;
trueRangeInt = (int) trueRange;
Value.Set(((Math.Min(CurrentBar + 1, Period) - 1 ) * Value[1] + (int) trueRange) / Math.Min(CurrentBar + 1, Period));
}
.
.
.
It displays x.xx not x

why???

thanks.

[8DTK8]

Thank you!

I do lots of thanking in advance, but here it is again after the fact...

Thank you! Thank you! Thank you! Thank you! Thank you!

I realize that these are all the most simplistic of programing considerations that anyone who has taken an intro class could answer, but to me whose first encounter with C# is through NT, it's gold.

It's much appreciated.

[NinjaTrader_JoshP]

If you want to convert double to int you can just cast it to an int.

(int) someDoubleVar

[8DTK8]

Thanks,

I guess a better question is how do you make the doube into an int. The Math.Round() that I used works just fine but the variable that's supposed to represent what is now a whole number still has to be a double instead of an int for it to compile.

I'm not sure if you're previous response was an answer to my question above. If so I will try to look it up somewhere else.

Thanks again,

[NinjaTrader_JoshP]

8DTK8,

Please search google for methods of rounding numbers in C#. You should be able to find resources capable of answering your question more in depth than anything I could offer.

[8DTK8]

How does one round to the nearest integer.
The particular reason is because I want to be able to take a fixed dollar amount, divide it by the risk to get the position size.
I'm coming up with errors because it's rarely a whole number.

double POSITIONsize = Math.Round(500/(ATR(Closes[0], 20)[0]*50));

EnterLongLimit(0, false, POSITIONsize, Lows[0][0] + OFFSETentry * TickSize, "Enter Long");

doesn't seem to do the trick because the system doesn't know what a .3 (for example of a contract is) and "int POSITIONsize" comes up with the same error.

Thank in advance.